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12x^2-31x-30=0
a = 12; b = -31; c = -30;
Δ = b2-4ac
Δ = -312-4·12·(-30)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-49}{2*12}=\frac{-18}{24} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+49}{2*12}=\frac{80}{24} =3+1/3 $
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